Single Resistances in a Tube Flow
In addition to the friction factor, individual resistances in ducts have to be taken into account. These resistances are created by the velocity, through bends, branches, valves, and other obstructions in the duct.
The single resistance factor Ј is defined as
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The I values for different types of resistances are available in hydraulics textbooks and also from the literature of pipe and valve manufacturers.
^Ploss |
2 P^m 2 |
1.5 |
0.9 |
0.8 |
103 1.5 2 3 4 5 6 8 104 1.5 2 3 4 J 6 8 10s 1.5 2 3 4 5 6 81061.5 2 3 4 5 6 107 Re |
The pressure loss and the corresponding resistance height in Eq. (4.53) and Eq. (4.54), respectively, are the sum of the friction losses and individual resistances:
(4.53)
When px = p2 and vOTl ance border 1: |
= 0, we obtain for the system defined by bal- |
= v |
Ml |
P _ |
Hf + (z-! — z2) , |
4vP8 |
2 / vml |
2g |
Hf+ tL-ll + (Z, _22) + Vl. Yjni |
P = QvPg |
2 g |
Pg |
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The form of Eq. (4.56) depends on the chosen balance border. The border can be chosen arbitrarily. When the balance space is chosen according to the balance border 2, the energy equation is
= hf + -…. !… ‘ * + Zy — Zt +………… ……………………………………. . (4.57)
QvPg 1 Pg ~ 2g
Using the values corresponding to the states 1′ and 2′, /y’ is the resistance height between V and 2′, and pr and pT are determined by the pressure loss and initial pressure. Other quantities are determined correspondingly. It is worth noting that there are no outflow losses in this case. Generally, it is wise to use energy balances in calculations.
The above is valid for a liquid flow, when the effect of compressibility can be ignored when calculating gas flows with small pressure differences. For instance, in ventilating duct work, air is not compressed, so the density is considered as constant. In HVAC technology a unit of pressure frequently used for convenience is a water column millimeter, 1 mm H->0 =10 Pa.
Posted in INDUSTRIAL VENTILATION DESIGN GUIDEBOOK