Analysis of the single zone system


—RA

подпись: —raTdb=72°F 0 = 50%

Q = 1.2xl06 Btn / h SHF = 0.8

Cooling

Coil

/

SA

подпись: sa

OA

подпись: oaMA

Qcc

Example

Cooling design conditions for OA are 16,262 cfm and 90°F db/72°F wb.

Design space cooling load is 1,200,000 Btu/h (80% sensible). Supply air temperature is 55°F. Determine (a) supply airflow rate and (b) cooling coil load.

Solution:

Plot known state on psych chart: OA, SA, and RA.

Assumption of perfect mixing => RA is equal to room air conditions => iRA=26.4 Btu/lbm

OA: iA=35.6 Btu/lbm, voa=14.1 ft3/lbm SA: iSA=21.2 Btu/lbm, vsa=13.1 fit3/lbm

(a) Flow rate O

(b) Cooling coil load O

Posted in Fundamentals of Heating. Ventilating, and Air-Conditioning


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